3[2x-3(x-2y)]+3y=0

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Solution for 3[2x-3(x-2y)]+3y=0 equation:


Simplifying
3[2x + -3(x + -2y)] + 3y = 0
3[2x + (x * -3 + -2y * -3)] + 3y = 0
3[2x + (-3x + 6y)] + 3y = 0

Combine like terms: 2x + -3x = -1x
3[-1x + 6y] + 3y = 0
[-1x * 3 + 6y * 3] + 3y = 0
[-3x + 18y] + 3y = 0

Combine like terms: 18y + 3y = 21y
-3x + 21y = 0

Solving
-3x + 21y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-21y' to each side of the equation.
-3x + 21y + -21y = 0 + -21y

Combine like terms: 21y + -21y = 0
-3x + 0 = 0 + -21y
-3x = 0 + -21y
Remove the zero:
-3x = -21y

Divide each side by '-3'.
x = 7y

Simplifying
x = 7y

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